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2112101112013 = 2391830483131
BaseRepresentation
bin11110101111000011000…
…010010101100011001101
321110220200221212101011121
4132233003002111203031
5234101040341041023
64254141424520541
7305410556143354
oct36570302254315
97426627771147
102112101112013
11744812019502
122a140a480151
1312422a14b309
1474324b2c99b
1539e197abd5d
hex1ebc30958cd

2112101112013 has 4 divisors (see below), whose sum is σ = 2203931595168. Its totient is φ = 2020270628860.

The previous prime is 2112101112007. The next prime is 2112101112053. The reversal of 2112101112013 is 3102111012112.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2112101112013 - 213 = 2112101103821 is a prime.

It is a super-2 number, since 2×21121011120132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2112101112053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45915241543 + ... + 45915241588.

It is an arithmetic number, because the mean of its divisors is an integer number (550982898792).

Almost surely, 22112101112013 is an apocalyptic number.

2112101112013 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

2112101112013 is a deficient number, since it is larger than the sum of its proper divisors (91830483155).

2112101112013 is an equidigital number, since it uses as much as digits as its factorization.

2112101112013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91830483154.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 2112101112013 its reverse (3102111012112), we get a palindrome (5214212124125).

Subtracting 2112101112013 from its reverse (3102111012112), we obtain a palindrome (990009900099).

The spelling of 2112101112013 in words is "two trillion, one hundred twelve billion, one hundred one million, one hundred twelve thousand, thirteen".

Divisors: 1 23 91830483131 2112101112013