Base | Representation |
---|---|
bin | 110000000001100000110110… |
… | …010000101101111100000111 |
3 | 1000200211111111112020220202002 |
4 | 300001200312100231330013 |
5 | 210140432013324201411 |
6 | 2025112345254135515 |
7 | 62326302125051504 |
oct | 6001406620557407 |
9 | 1020744445226662 |
10 | 211210222100231 |
11 | 61330830155682 |
12 | 1b831b5805159b |
13 | 90b1066713c03 |
14 | 3a228b4ad64ab |
15 | 19640e12ed33b |
hex | c0183642df07 |
211210222100231 has 2 divisors, whose sum is σ = 211210222100232. Its totient is φ = 211210222100230.
The previous prime is 211210222100177. The next prime is 211210222100249. The reversal of 211210222100231 is 132001222012112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211210222100231 - 210 = 211210222099207 is a prime.
It is a super-3 number, since 3×2112102221002313 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211210222100131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605111050115 + 105605111050116.
It is an arithmetic number, because the mean of its divisors is an integer number (105605111050116).
Almost surely, 2211210222100231 is an apocalyptic number.
211210222100231 is a deficient number, since it is larger than the sum of its proper divisors (1).
211210222100231 is an equidigital number, since it uses as much as digits as its factorization.
211210222100231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 211210222100231 its reverse (132001222012112), we get a palindrome (343211444112343).
The spelling of 211210222100231 in words is "two hundred eleven trillion, two hundred ten billion, two hundred twenty-two million, one hundred thousand, two hundred thirty-one".
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