Search a number
-
+
211211110207 is a prime number
BaseRepresentation
bin1100010010110100101…
…0011100011100111111
3202012011122222002111101
43010231022130130333
511430030021011312
6241010135033531
721155002546336
oct3045512343477
9665148862441
10211211110207
1181635190239
1234b2620b8a7
1316bbcbc0ab6
14a319026d1d
155762814a57
hex312d29c73f

211211110207 has 2 divisors, whose sum is σ = 211211110208. Its totient is φ = 211211110206.

The previous prime is 211211110183. The next prime is 211211110217. The reversal of 211211110207 is 702011112112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211211110207 - 215 = 211211077439 is a prime.

It is a super-2 number, since 2×2112111102072 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211211110217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605555103 + 105605555104.

It is an arithmetic number, because the mean of its divisors is an integer number (105605555104).

Almost surely, 2211211110207 is an apocalyptic number.

211211110207 is a deficient number, since it is larger than the sum of its proper divisors (1).

211211110207 is an equidigital number, since it uses as much as digits as its factorization.

211211110207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 211211110207 its reverse (702011112112), we get a palindrome (913222222319).

The spelling of 211211110207 in words is "two hundred eleven billion, two hundred eleven million, one hundred ten thousand, two hundred seven".