Base | Representation |
---|---|
bin | 1100010010110100101… |
… | …0011100011100111111 |
3 | 202012011122222002111101 |
4 | 3010231022130130333 |
5 | 11430030021011312 |
6 | 241010135033531 |
7 | 21155002546336 |
oct | 3045512343477 |
9 | 665148862441 |
10 | 211211110207 |
11 | 81635190239 |
12 | 34b2620b8a7 |
13 | 16bbcbc0ab6 |
14 | a319026d1d |
15 | 5762814a57 |
hex | 312d29c73f |
211211110207 has 2 divisors, whose sum is σ = 211211110208. Its totient is φ = 211211110206.
The previous prime is 211211110183. The next prime is 211211110217. The reversal of 211211110207 is 702011112112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211211110207 - 215 = 211211077439 is a prime.
It is a super-2 number, since 2×2112111102072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211211110217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605555103 + 105605555104.
It is an arithmetic number, because the mean of its divisors is an integer number (105605555104).
Almost surely, 2211211110207 is an apocalyptic number.
211211110207 is a deficient number, since it is larger than the sum of its proper divisors (1).
211211110207 is an equidigital number, since it uses as much as digits as its factorization.
211211110207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 211211110207 its reverse (702011112112), we get a palindrome (913222222319).
The spelling of 211211110207 in words is "two hundred eleven billion, two hundred eleven million, one hundred ten thousand, two hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •