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211211111012023 is a prime number
BaseRepresentation
bin110000000001100001101011…
…001111101001011010110111
31000200211120210110220022111001
4300001201223033221122313
5210140440323404341043
62025113013410424131
762326333140506203
oct6001415317513267
91020746713808431
10211211111012023
11613311469a4221
121b832165892047
1390b1178927615
143a2295aba7b03
15196414438974d
hexc0186b3e96b7

211211111012023 has 2 divisors, whose sum is σ = 211211111012024. Its totient is φ = 211211111012022.

The previous prime is 211211111011963. The next prime is 211211111012107. The reversal of 211211111012023 is 320210111112112.

211211111012023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211211111012023 - 229 = 211210574141111 is a prime.

It is a super-2 number, since 2×2112111110120232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211211111012123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605555506011 + 105605555506012.

It is an arithmetic number, because the mean of its divisors is an integer number (105605555506012).

Almost surely, 2211211111012023 is an apocalyptic number.

211211111012023 is a deficient number, since it is larger than the sum of its proper divisors (1).

211211111012023 is an equidigital number, since it uses as much as digits as its factorization.

211211111012023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 211211111012023 its reverse (320210111112112), we get a palindrome (531421222124135).

The spelling of 211211111012023 in words is "two hundred eleven trillion, two hundred eleven billion, one hundred eleven million, twelve thousand, twenty-three".