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211211210200147 is a prime number
BaseRepresentation
bin110000000001100001110001…
…001010000001010001010011
31000200211121001101112121000021
4300001201301022001101103
5210140441024302401042
62025113031312404311
762326335453550333
oct6001416112012123
91020747041477007
10211211210200147
1161331197990783
121b832192b46697
1390b1193345711
143a2296a0270c3
15196414ce2d867
hexc01871281453

211211210200147 has 2 divisors, whose sum is σ = 211211210200148. Its totient is φ = 211211210200146.

The previous prime is 211211210200127. The next prime is 211211210200229. The reversal of 211211210200147 is 741002012112112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211211210200147 - 211 = 211211210198099 is a prime.

It is a super-2 number, since 2×2112112102001472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211211210200127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605605100073 + 105605605100074.

It is an arithmetic number, because the mean of its divisors is an integer number (105605605100074).

Almost surely, 2211211210200147 is an apocalyptic number.

211211210200147 is a deficient number, since it is larger than the sum of its proper divisors (1).

211211210200147 is an equidigital number, since it uses as much as digits as its factorization.

211211210200147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 448, while the sum is 25.

Adding to 211211210200147 its reverse (741002012112112), we get a palindrome (952213222312259).

The spelling of 211211210200147 in words is "two hundred eleven trillion, two hundred eleven billion, two hundred ten million, two hundred thousand, one hundred forty-seven".