Base | Representation |
---|---|
bin | 110000000001100001110001… |
… | …010001010001010111101111 |
3 | 1000200211121001112010011122001 |
4 | 300001201301101101113233 |
5 | 210140441030244213403 |
6 | 2025113031421233131 |
7 | 62326335505655434 |
oct | 6001416121212757 |
9 | 1020747045104561 |
10 | 211211212101103 |
11 | 61331198a69a15 |
12 | 1b8321937027a7 |
13 | 90b119385ca46 |
14 | 3a2296a39db8b |
15 | 196414d1a6c1d |
hex | c018714515ef |
211211212101103 has 2 divisors, whose sum is σ = 211211212101104. Its totient is φ = 211211212101102.
The previous prime is 211211212101067. The next prime is 211211212101133. The reversal of 211211212101103 is 301101212112112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211211212101103 - 225 = 211211178546671 is a prime.
It is a super-2 number, since 2×2112112121011032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211211212101133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605606050551 + 105605606050552.
It is an arithmetic number, because the mean of its divisors is an integer number (105605606050552).
Almost surely, 2211211212101103 is an apocalyptic number.
211211212101103 is a deficient number, since it is larger than the sum of its proper divisors (1).
211211212101103 is an equidigital number, since it uses as much as digits as its factorization.
211211212101103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 211211212101103 its reverse (301101212112112), we get a palindrome (512312424213215).
The spelling of 211211212101103 in words is "two hundred eleven trillion, two hundred eleven billion, two hundred twelve million, one hundred one thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •