| Base | Representation |
|---|---|
| bin | 11110101111000011101… |
| … | …100010111011111111000 |
| 3 | 21110220201201121011001200 |
| 4 | 132233003230113133320 |
| 5 | 234101101201130130 |
| 6 | 4254142501014200 |
| 7 | 305411051613033 |
| oct | 36570354273770 |
| 9 | 7426651534050 |
| 10 | 2112112130040 |
| 11 | 744818264510 |
| 12 | 2a14120b4360 |
| 13 | 12422c508363 |
| 14 | 7432639a01a |
| 15 | 39e1a736760 |
| hex | 1ebc3b177f8 |
2112112130040 has 384 divisors, whose sum is σ = 7761010982400. Its totient is φ = 493452610560.
The previous prime is 2112112130039. The next prime is 2112112130047. The reversal of 2112112130040 is 400312112112.
2112112130040 is a `hidden beast` number, since 211 + 2 + 112 + 1 + 300 + 40 = 666.
It is a super-2 number, since 2×21121121300402 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 2112112129995 and 2112112130022.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2112112130047) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 62800669 + ... + 62834291.
It is an arithmetic number, because the mean of its divisors is an integer number (20210966100).
Almost surely, 22112112130040 is an apocalyptic number.
2112112130040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 2112112130040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3880505491200).
2112112130040 is an abundant number, since it is smaller than the sum of its proper divisors (5648898852360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2112112130040 is a wasteful number, since it uses less digits than its factorization.
2112112130040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34227 (or 34220 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 2112112130040 its reverse (400312112112), we get a palindrome (2512424242152).
The spelling of 2112112130040 in words is "two trillion, one hundred twelve billion, one hundred twelve million, one hundred thirty thousand, forty".
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