Base | Representation |
---|---|
bin | 110000000001100001110001… |
… | …010101111001100110011111 |
3 | 1000200211121001121101211001022 |
4 | 300001201301111321212133 |
5 | 210140441031102030323 |
6 | 2025113031503234355 |
7 | 62326335522201065 |
oct | 6001416125714637 |
9 | 1020747047354038 |
10 | 211211213314463 |
11 | 6133119971859a |
12 | 1b832193ba89bb |
13 | 90b1193b960cb |
14 | 3a2296a5d8035 |
15 | 196414d3464c8 |
hex | c0187157999f |
211211213314463 has 2 divisors, whose sum is σ = 211211213314464. Its totient is φ = 211211213314462.
The previous prime is 211211213314427. The next prime is 211211213314523. The reversal of 211211213314463 is 364413312112112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211211213314463 - 224 = 211211196537247 is a prime.
It is a super-2 number, since 2×2112112133144632 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211211213394463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605606657231 + 105605606657232.
It is an arithmetic number, because the mean of its divisors is an integer number (105605606657232).
Almost surely, 2211211213314463 is an apocalyptic number.
211211213314463 is a deficient number, since it is larger than the sum of its proper divisors (1).
211211213314463 is an equidigital number, since it uses as much as digits as its factorization.
211211213314463 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20736, while the sum is 35.
Adding to 211211213314463 its reverse (364413312112112), we get a palindrome (575624525426575).
The spelling of 211211213314463 in words is "two hundred eleven trillion, two hundred eleven billion, two hundred thirteen million, three hundred fourteen thousand, four hundred sixty-three".
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