Base | Representation |
---|---|
bin | 1100010010110100101… |
… | …0110101110110001111 |
3 | 202012011200011101011211 |
4 | 3010231022311312033 |
5 | 11430030032323343 |
6 | 241010141155251 |
7 | 21155003461522 |
oct | 3045512656617 |
9 | 665150141154 |
10 | 211211214223 |
11 | 816352513a9 |
12 | 34b2625bb27 |
13 | 16bbcc29249 |
14 | a319052bb9 |
15 | 576283579d |
hex | 312d2b5d8f |
211211214223 has 2 divisors, whose sum is σ = 211211214224. Its totient is φ = 211211214222.
The previous prime is 211211214217. The next prime is 211211214259. The reversal of 211211214223 is 322412112112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211211214223 - 221 = 211209117071 is a prime.
It is a super-2 number, since 2×2112112142232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211211214194 and 211211214203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211211214523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605607111 + 105605607112.
It is an arithmetic number, because the mean of its divisors is an integer number (105605607112).
Almost surely, 2211211214223 is an apocalyptic number.
211211214223 is a deficient number, since it is larger than the sum of its proper divisors (1).
211211214223 is an equidigital number, since it uses as much as digits as its factorization.
211211214223 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 384, while the sum is 22.
Adding to 211211214223 its reverse (322412112112), we get a palindrome (533623326335).
The spelling of 211211214223 in words is "two hundred eleven billion, two hundred eleven million, two hundred fourteen thousand, two hundred twenty-three".
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