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211211214223 is a prime number
BaseRepresentation
bin1100010010110100101…
…0110101110110001111
3202012011200011101011211
43010231022311312033
511430030032323343
6241010141155251
721155003461522
oct3045512656617
9665150141154
10211211214223
11816352513a9
1234b2625bb27
1316bbcc29249
14a319052bb9
15576283579d
hex312d2b5d8f

211211214223 has 2 divisors, whose sum is σ = 211211214224. Its totient is φ = 211211214222.

The previous prime is 211211214217. The next prime is 211211214259. The reversal of 211211214223 is 322412112112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211211214223 - 221 = 211209117071 is a prime.

It is a super-2 number, since 2×2112112142232 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211211214194 and 211211214203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211211214523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605607111 + 105605607112.

It is an arithmetic number, because the mean of its divisors is an integer number (105605607112).

Almost surely, 2211211214223 is an apocalyptic number.

211211214223 is a deficient number, since it is larger than the sum of its proper divisors (1).

211211214223 is an equidigital number, since it uses as much as digits as its factorization.

211211214223 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 384, while the sum is 22.

Adding to 211211214223 its reverse (322412112112), we get a palindrome (533623326335).

The spelling of 211211214223 in words is "two hundred eleven billion, two hundred eleven million, two hundred fourteen thousand, two hundred twenty-three".