Base | Representation |
---|---|
bin | 1001100110101101001001… |
… | …11110011000110010001011 |
3 | 2202210011022022022200011022 |
4 | 10303112210332120302023 |
5 | 10232022024213343144 |
6 | 112530524241423055 |
7 | 4306644043626131 |
oct | 463264476306213 |
9 | 82704268280138 |
10 | 21121122012299 |
11 | 6803465827541 |
12 | 24514b903aa8b |
13 | ba293705392a |
14 | 5303a6a39751 |
15 | 26961ed35cee |
hex | 1335a4f98c8b |
21121122012299 has 2 divisors, whose sum is σ = 21121122012300. Its totient is φ = 21121122012298.
The previous prime is 21121122012259. The next prime is 21121122012433. The reversal of 21121122012299 is 99221022112112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21121122012299 is a prime.
It is a super-2 number, since 2×211211220122992 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (21121122012259) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560561006149 + 10560561006150.
It is an arithmetic number, because the mean of its divisors is an integer number (10560561006150).
Almost surely, 221121122012299 is an apocalyptic number.
21121122012299 is a deficient number, since it is larger than the sum of its proper divisors (1).
21121122012299 is an equidigital number, since it uses as much as digits as its factorization.
21121122012299 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 35.
The spelling of 21121122012299 in words is "twenty-one trillion, one hundred twenty-one billion, one hundred twenty-two million, twelve thousand, two hundred ninety-nine".
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