21121122012433 has 2 divisors, whose sum is σ = 21121122012434. Its totient is φ = 21121122012432.

The previous prime is 21121122012299. The next prime is 21121122012479. The reversal of 21121122012433 is 33421022112112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15896711236624 + 5224410775809 = 3987068^2 + 2285697^2 .

It is a cyclic number.

It is not a de Polignac number, because 21121122012433 - 2⁴¹ = 18922098756881 is a prime.

It is a super-2 number, since 2×21121122012433² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21121122012398 and 21121122012407.

It is not a weakly prime, because it can be changed into another prime (21121122012493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560561006216 + 10560561006217.

It is an arithmetic number, because the mean of its divisors is an integer number (10560561006217).

Almost surely, 2^{21121122012433} is an apocalyptic number.

It is an amenable number.

21121122012433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21121122012433 is an equidigital number, since it uses as much as digits as its factorization.

21121122012433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 21121122012433 its reverse (33421022112112), we get a palindrome (54542144124545).

The spelling of 21121122012433 in words is "twenty-one trillion, one hundred twenty-one billion, one hundred twenty-two million, twelve thousand, four hundred thirty-three".