Base | Representation |
---|---|
bin | 1100010010110100101… |
… | …1010010001101111111 |
3 | 202012011200101021120211 |
4 | 3010231023102031333 |
5 | 11430030100033211 |
6 | 241010143453251 |
7 | 21155004454363 |
oct | 3045513221577 |
9 | 665150337524 |
10 | 211211330431 |
11 | 81635320742 |
12 | 34b262b7227 |
13 | 16bbcc6a0ca |
14 | a3190832a3 |
15 | 5762859e21 |
hex | 312d2d237f |
211211330431 has 2 divisors, whose sum is σ = 211211330432. Its totient is φ = 211211330430.
The previous prime is 211211330417. The next prime is 211211330437. The reversal of 211211330431 is 134033112112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211211330431 is a prime.
It is a super-2 number, since 2×2112113304312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211211330437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605665215 + 105605665216.
It is an arithmetic number, because the mean of its divisors is an integer number (105605665216).
Almost surely, 2211211330431 is an apocalyptic number.
211211330431 is a deficient number, since it is larger than the sum of its proper divisors (1).
211211330431 is an equidigital number, since it uses as much as digits as its factorization.
211211330431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 211211330431 its reverse (134033112112), we get a palindrome (345244442543).
The spelling of 211211330431 in words is "two hundred eleven billion, two hundred eleven million, three hundred thirty thousand, four hundred thirty-one".
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