Base | Representation |
---|---|
bin | 11110101111000011110… |
… | …101000001110100111101 |
3 | 21110220201212212111122111 |
4 | 132233003311001310331 |
5 | 234101102241304243 |
6 | 4254143021414021 |
7 | 305411110120462 |
oct | 36570365016475 |
9 | 7426655774574 |
10 | 2112114400573 |
11 | 744819575391 |
12 | 2a1412a0a311 |
13 | 12422cb21978 |
14 | 743267cb669 |
15 | 39e1aa3439d |
hex | 1ebc3d41d3d |
2112114400573 has 2 divisors, whose sum is σ = 2112114400574. Its totient is φ = 2112114400572.
The previous prime is 2112114400541. The next prime is 2112114400619. The reversal of 2112114400573 is 3750044112112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1722086672089 + 390027728484 = 1312283^2 + 624522^2 .
It is a cyclic number.
It is not a de Polignac number, because 2112114400573 - 25 = 2112114400541 is a prime.
It is a super-2 number, since 2×21121144005732 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112114400873) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056057200286 + 1056057200287.
It is an arithmetic number, because the mean of its divisors is an integer number (1056057200287).
Almost surely, 22112114400573 is an apocalyptic number.
It is an amenable number.
2112114400573 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112114400573 is an equidigital number, since it uses as much as digits as its factorization.
2112114400573 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 31.
Adding to 2112114400573 its reverse (3750044112112), we get a palindrome (5862158512685).
The spelling of 2112114400573 in words is "two trillion, one hundred twelve billion, one hundred fourteen million, four hundred thousand, five hundred seventy-three".
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