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211212100202102 = 22922716042237597
BaseRepresentation
bin110000000001100010100110…
…001101000110111001110110
31000200211200100102020101011122
4300001202212031012321312
5210140444340122431402
62025113255504303542
762326366511465246
oct6001424615067166
91020750312211148
10211212100202102
116133160430438a
121b8323a1011bb2
1390b12a584b3ac
143a22a122ddb26
1519641a1132ca2
hexc018a6346e76

211212100202102 has 16 divisors (see below), whose sum is σ = 329186715510960. Its totient is φ = 101515279507488.

The previous prime is 211212100202041. The next prime is 211212100202107. The reversal of 211212100202102 is 201202001212112.

It is a super-2 number, since 2×2112121002021022 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211212100202107) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8021105633 + ... + 8021131964.

It is an arithmetic number, because the mean of its divisors is an integer number (20574169719435).

Almost surely, 2211212100202102 is an apocalyptic number.

211212100202102 is a deficient number, since it is larger than the sum of its proper divisors (117974615308858).

211212100202102 is a wasteful number, since it uses less digits than its factorization.

211212100202102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16042237855.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 211212100202102 its reverse (201202001212112), we get a palindrome (412414101414214).

The spelling of 211212100202102 in words is "two hundred eleven trillion, two hundred twelve billion, one hundred million, two hundred two thousand, one hundred two".

Divisors: 1 2 29 58 227 454 6583 13166 16042237597 32084475194 465224890313 930449780626 3641587934519 7283175869038 105606050101051 211212100202102