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2112121043293 is a prime number
BaseRepresentation
bin11110101111000100001…
…110010111100101011101
321110220202100100222202011
4132233010032113211131
5234101110441341133
64254143420031221
7305411220435142
oct36570416274535
97426670328664
102112121043293
117448222a2138
122a1415092511
13124231309381
147432763a3c9
1539e1b3e76cd
hex1ebc439795d

2112121043293 has 2 divisors, whose sum is σ = 2112121043294. Its totient is φ = 2112121043292.

The previous prime is 2112121043273. The next prime is 2112121043377. The reversal of 2112121043293 is 3923401212112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1470779541049 + 641341502244 = 1212757^2 + 800838^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112121043293 - 217 = 2112120912221 is a prime.

It is a super-3 number, since 3×21121210432933 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2112121043233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056060521646 + 1056060521647.

It is an arithmetic number, because the mean of its divisors is an integer number (1056060521647).

Almost surely, 22112121043293 is an apocalyptic number.

It is an amenable number.

2112121043293 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112121043293 is an equidigital number, since it uses as much as digits as its factorization.

2112121043293 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 31.

The spelling of 2112121043293 in words is "two trillion, one hundred twelve billion, one hundred twenty-one million, forty-three thousand, two hundred ninety-three".