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21121211050211 is a prime number
BaseRepresentation
bin1001100110101101010100…
…10010000010100011100011
32202210011112111212021012202
410303112222102002203203
510232022220012101321
6112530541142043415
74306646204503646
oct463265222024343
982704474767182
1021121211050211
116803501010a98
122451522a1956b
13ba294c62999c
145303b47b5a5d
15269627a7270b
hex1335aa4828e3

21121211050211 has 2 divisors, whose sum is σ = 21121211050212. Its totient is φ = 21121211050210.

The previous prime is 21121211050193. The next prime is 21121211050213. The reversal of 21121211050211 is 11205011212112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21121211050211 - 226 = 21121143941347 is a prime.

It is a super-2 number, since 2×211212110502112 (a number of 27 digits) contains 22 as substring.

Together with 21121211050213, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (21121211050213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560605525105 + 10560605525106.

It is an arithmetic number, because the mean of its divisors is an integer number (10560605525106).

Almost surely, 221121211050211 is an apocalyptic number.

21121211050211 is a deficient number, since it is larger than the sum of its proper divisors (1).

21121211050211 is an equidigital number, since it uses as much as digits as its factorization.

21121211050211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 20.

Adding to 21121211050211 its reverse (11205011212112), we get a palindrome (32326222262323).

The spelling of 21121211050211 in words is "twenty-one trillion, one hundred twenty-one billion, two hundred eleven million, fifty thousand, two hundred eleven".