Base | Representation |
---|---|
bin | 11110101111000100001… |
… | …110101000011010001111 |
3 | 21110220202100111111021112 |
4 | 132233010032220122033 |
5 | 234101111001042312 |
6 | 4254143421322235 |
7 | 305411221143101 |
oct | 36570416503217 |
9 | 7426670444245 |
10 | 2112121112207 |
11 | 744822339997 |
12 | 2a141510637b |
13 | 124231331852 |
14 | 74327657571 |
15 | 39e1b40cd22 |
hex | 1ebc43a868f |
2112121112207 has 2 divisors, whose sum is σ = 2112121112208. Its totient is φ = 2112121112206.
The previous prime is 2112121112113. The next prime is 2112121112237. The reversal of 2112121112207 is 7022111212112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2112121112207 - 214 = 2112121095823 is a prime.
It is a super-2 number, since 2×21121211122072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112121112237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056060556103 + 1056060556104.
It is an arithmetic number, because the mean of its divisors is an integer number (1056060556104).
Almost surely, 22112121112207 is an apocalyptic number.
2112121112207 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112121112207 is an equidigital number, since it uses as much as digits as its factorization.
2112121112207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 2112121112207 its reverse (7022111212112), we get a palindrome (9134232324319).
The spelling of 2112121112207 in words is "two trillion, one hundred twelve billion, one hundred twenty-one million, one hundred twelve thousand, two hundred seven".
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