Base | Representation |
---|---|
bin | 1100010010110100111… |
… | …0010011100000000001 |
3 | 202012011201212111120101 |
4 | 3010231032103200001 |
5 | 11430030300401423 |
6 | 241010212442401 |
7 | 21155014262446 |
oct | 3045516234001 |
9 | 665151774511 |
10 | 211212122113 |
11 | 81635811523 |
12 | 34b26619401 |
13 | 16bc0186565 |
14 | a31920b9cd |
15 | 57629647ad |
hex | 312d393801 |
211212122113 has 2 divisors, whose sum is σ = 211212122114. Its totient is φ = 211212122112.
The previous prime is 211212122021. The next prime is 211212122141. The reversal of 211212122113 is 311221212112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 184274449984 + 26937672129 = 429272^2 + 164127^2 .
It is a cyclic number.
It is not a de Polignac number, because 211212122113 - 213 = 211212113921 is a prime.
It is a super-2 number, since 2×2112121221132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211212132113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606061056 + 105606061057.
It is an arithmetic number, because the mean of its divisors is an integer number (105606061057).
Almost surely, 2211212122113 is an apocalyptic number.
It is an amenable number.
211212122113 is a deficient number, since it is larger than the sum of its proper divisors (1).
211212122113 is an equidigital number, since it uses as much as digits as its factorization.
211212122113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 96, while the sum is 19.
Adding to 211212122113 its reverse (311221212112), we get a palindrome (522433334225).
The spelling of 211212122113 in words is "two hundred eleven billion, two hundred twelve million, one hundred twenty-two thousand, one hundred thirteen".
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