Base | Representation |
---|---|
bin | 11110101111000100011… |
… | …010111101001011110011 |
3 | 21110220202120120122010112 |
4 | 132233010122331023303 |
5 | 234101112312434102 |
6 | 4254144014451535 |
7 | 305411260460306 |
oct | 36570432751363 |
9 | 7426676518115 |
10 | 2112124343027 |
11 | 744824146296 |
12 | 2a1416203bab |
13 | 124231bc328a |
14 | 74327c58b3d |
15 | 39e1b84a252 |
hex | 1ebc46bd2f3 |
2112124343027 has 2 divisors, whose sum is σ = 2112124343028. Its totient is φ = 2112124343026.
The previous prime is 2112124342997. The next prime is 2112124343041. The reversal of 2112124343027 is 7203434212112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2112124343027 - 216 = 2112124277491 is a prime.
It is a super-2 number, since 2×21121243430272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2112124342984 and 2112124343002.
It is not a weakly prime, because it can be changed into another prime (2112124343827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056062171513 + 1056062171514.
It is an arithmetic number, because the mean of its divisors is an integer number (1056062171514).
Almost surely, 22112124343027 is an apocalyptic number.
2112124343027 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112124343027 is an equidigital number, since it uses as much as digits as its factorization.
2112124343027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 2112124343027 its reverse (7203434212112), we get a palindrome (9315558555139).
The spelling of 2112124343027 in words is "two trillion, one hundred twelve billion, one hundred twenty-four million, three hundred forty-three thousand, twenty-seven".
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