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211213007 is a prime number
BaseRepresentation
bin11001001011011…
…01101011001111
3112201102201202222
430211231223033
5413032304012
632543005555
75143165235
oct1445555317
9481381688
10211213007
11a9251505
125a8998bb
13349b2015
14200a0955
1513821972
hexc96dacf

211213007 has 2 divisors, whose sum is σ = 211213008. Its totient is φ = 211213006.

The previous prime is 211212973. The next prime is 211213021. The reversal of 211213007 is 700312112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211213007 - 26 = 211212943 is a prime.

It is a super-2 number, since 2×2112130072 = 89221868651964098, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211213087) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606503 + 105606504.

It is an arithmetic number, because the mean of its divisors is an integer number (105606504).

Almost surely, 2211213007 is an apocalyptic number.

211213007 is a deficient number, since it is larger than the sum of its proper divisors (1).

211213007 is an equidigital number, since it uses as much as digits as its factorization.

211213007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 211213007 is about 14533.1692001435. The cubic root of 211213007 is about 595.5344462423.

Adding to 211213007 its reverse (700312112), we get a palindrome (911525119).

The spelling of 211213007 in words is "two hundred eleven million, two hundred thirteen thousand, seven".