Base | Representation |
---|---|
bin | 10011101010111011… |
… | …011010100100000011 |
3 | 2000111222110212112212 |
4 | 103222323122210003 |
5 | 321224024004102 |
6 | 13411503012335 |
7 | 1345256125043 |
oct | 235273324403 |
9 | 60458425485 |
10 | 21121313027 |
11 | 8a59481101 |
12 | 411559a0ab |
13 | 1cb7aab579 |
14 | 10451b1723 |
15 | 839411c52 |
hex | 4eaeda903 |
21121313027 has 2 divisors, whose sum is σ = 21121313028. Its totient is φ = 21121313026.
The previous prime is 21121312999. The next prime is 21121313029. The reversal of 21121313027 is 72031312112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21121313027 - 26 = 21121312963 is a prime.
It is a super-2 number, since 2×211213130272 (a number of 21 digits) contains 22 as substring.
Together with 21121313029, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 21121312993 and 21121313011.
It is not a weakly prime, because it can be changed into another prime (21121313029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560656513 + 10560656514.
It is an arithmetic number, because the mean of its divisors is an integer number (10560656514).
Almost surely, 221121313027 is an apocalyptic number.
21121313027 is a deficient number, since it is larger than the sum of its proper divisors (1).
21121313027 is an equidigital number, since it uses as much as digits as its factorization.
21121313027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 21121313027 its reverse (72031312112), we get a palindrome (93152625139).
The spelling of 21121313027 in words is "twenty-one billion, one hundred twenty-one million, three hundred thirteen thousand, twenty-seven".
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