211213202312141 has 2 divisors, whose sum is σ = 211213202312142. Its totient is φ = 211213202312140.

The previous prime is 211213202312081. The next prime is 211213202312191. The reversal of 211213202312141 is 141213202312112.

211213202312141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 196273655452900 + 14939546859241 = 14009770^2 + 3865171^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211213202312141 is a prime.

It is a super-2 number, since 2×211213202312141² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211213202312141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211213202312191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606601156070 + 105606601156071.

It is an arithmetic number, because the mean of its divisors is an integer number (105606601156071).

Almost surely, 2^{211213202312141} is an apocalyptic number.

It is an amenable number.

211213202312141 is a deficient number, since it is larger than the sum of its proper divisors (1).

211213202312141 is an equidigital number, since it uses as much as digits as its factorization.

211213202312141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 211213202312141 its reverse (141213202312112), we get a palindrome (352426404624253).

The spelling of 211213202312141 in words is "two hundred eleven trillion, two hundred thirteen billion, two hundred two million, three hundred twelve thousand, one hundred forty-one".