Base | Representation |
---|---|
bin | 1001100110101101100011… |
… | …11111100000110101000011 |
3 | 2202210011212112021111010121 |
4 | 10303112301333200311003 |
5 | 10232023001121124303 |
6 | 112531002042441111 |
7 | 4306652335163464 |
oct | 463266177406503 |
9 | 82704775244117 |
10 | 21121340411203 |
11 | 68035680368aa |
12 | 245155a203197 |
13 | ba2970380656 |
14 | 5303c7a4ad6b |
15 | 2696340c69bd |
hex | 1335b1fe0d43 |
21121340411203 has 2 divisors, whose sum is σ = 21121340411204. Its totient is φ = 21121340411202.
The previous prime is 21121340411191. The next prime is 21121340411239. The reversal of 21121340411203 is 30211404312112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21121340411203 - 221 = 21121338314051 is a prime.
It is a super-2 number, since 2×211213404112032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21121340411903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560670205601 + 10560670205602.
It is an arithmetic number, because the mean of its divisors is an integer number (10560670205602).
Almost surely, 221121340411203 is an apocalyptic number.
21121340411203 is a deficient number, since it is larger than the sum of its proper divisors (1).
21121340411203 is an equidigital number, since it uses as much as digits as its factorization.
21121340411203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 21121340411203 its reverse (30211404312112), we get a palindrome (51332744723315).
The spelling of 21121340411203 in words is "twenty-one trillion, one hundred twenty-one billion, three hundred forty million, four hundred eleven thousand, two hundred three".
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