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21121340411203 is a prime number
BaseRepresentation
bin1001100110101101100011…
…11111100000110101000011
32202210011212112021111010121
410303112301333200311003
510232023001121124303
6112531002042441111
74306652335163464
oct463266177406503
982704775244117
1021121340411203
1168035680368aa
12245155a203197
13ba2970380656
145303c7a4ad6b
152696340c69bd
hex1335b1fe0d43

21121340411203 has 2 divisors, whose sum is σ = 21121340411204. Its totient is φ = 21121340411202.

The previous prime is 21121340411191. The next prime is 21121340411239. The reversal of 21121340411203 is 30211404312112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21121340411203 - 221 = 21121338314051 is a prime.

It is a super-2 number, since 2×211213404112032 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21121340411903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560670205601 + 10560670205602.

It is an arithmetic number, because the mean of its divisors is an integer number (10560670205602).

Almost surely, 221121340411203 is an apocalyptic number.

21121340411203 is a deficient number, since it is larger than the sum of its proper divisors (1).

21121340411203 is an equidigital number, since it uses as much as digits as its factorization.

21121340411203 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 21121340411203 its reverse (30211404312112), we get a palindrome (51332744723315).

The spelling of 21121340411203 in words is "twenty-one trillion, one hundred twenty-one billion, three hundred forty million, four hundred eleven thousand, two hundred three".