Base | Representation |
---|---|
bin | 1100010010110101010… |
… | …1110110011010001111 |
3 | 202012011212120222212120 |
4 | 3010231111312122033 |
5 | 11430031302200421 |
6 | 241010323104023 |
7 | 21155040141300 |
oct | 3045525663217 |
9 | 665155528776 |
10 | 211214100111 |
11 | 81636942633 |
12 | 34b27212013 |
13 | 16bc06c9981 |
14 | a3195a47a7 |
15 | 5762c058c6 |
hex | 312d57668f |
211214100111 has 24 divisors (see below), whose sum is σ = 327638692224. Its totient is φ = 120678551280.
The previous prime is 211214100103. The next prime is 211214100137. The reversal of 211214100111 is 111001412112.
It is a happy number.
It is not a de Polignac number, because 211214100111 - 23 = 211214100103 is a prime.
It is a super-2 number, since 2×2112141001112 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211214102111) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1135276 + ... + 1308158.
It is an arithmetic number, because the mean of its divisors is an integer number (13651612176).
Almost surely, 2211214100111 is an apocalyptic number.
211214100111 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
211214100111 is a deficient number, since it is larger than the sum of its proper divisors (116424592113).
211214100111 is a wasteful number, since it uses less digits than its factorization.
211214100111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 181211 (or 181204 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 15.
Adding to 211214100111 its reverse (111001412112), we get a palindrome (322215512223).
The spelling of 211214100111 in words is "two hundred eleven billion, two hundred fourteen million, one hundred thousand, one hundred eleven".
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