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2112141044444 = 22528035261111
BaseRepresentation
bin11110101111000101011…
…010101010101011011100
321110220210202000011011112
4132233011122222223130
5234101131101410234
64254145412441152
7305411552440424
oct36570532525334
97426722004145
102112141044444
11744832613312
122a141b9191b8
131242354c0182
147432a165484
1539e1d048ace
hex1ebc56aaadc

2112141044444 has 6 divisors (see below), whose sum is σ = 3696246827784. Its totient is φ = 1056070522220.

The previous prime is 2112141044437. The next prime is 2112141044459. The reversal of 2112141044444 is 4444401412112.

It is a super-2 number, since 2×21121410444442 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2112141044444.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 264017630552 + ... + 264017630559.

It is an arithmetic number, because the mean of its divisors is an integer number (616041137964).

Almost surely, 22112141044444 is an apocalyptic number.

It is an amenable number.

2112141044444 is a deficient number, since it is larger than the sum of its proper divisors (1584105783340).

2112141044444 is a wasteful number, since it uses less digits than its factorization.

2112141044444 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 528035261115 (or 528035261113 counting only the distinct ones).

The product of its (nonzero) digits is 16384, while the sum is 32.

Adding to 2112141044444 its reverse (4444401412112), we get a palindrome (6556542456556).

The spelling of 2112141044444 in words is "two trillion, one hundred twelve billion, one hundred forty-one million, forty-four thousand, four hundred forty-four".

Divisors: 1 2 4 528035261111 1056070522222 2112141044444