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211214131243 is a prime number
BaseRepresentation
bin1100010010110101010…
…1111110000000101011
3202012011212122120120121
43010231111332000223
511430031304144433
6241010323504111
721155040331123
oct3045525760053
9665155576517
10211214131243
1181636963a65
1234b27228037
1316bc070abab
14a3195b1c83
155762c0ec2d
hex312d57e02b

211214131243 has 2 divisors, whose sum is σ = 211214131244. Its totient is φ = 211214131242.

The previous prime is 211214131159. The next prime is 211214131301. The reversal of 211214131243 is 342131412112.

211214131243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211214131243 - 29 = 211214130731 is a prime.

It is a super-2 number, since 2×2112141312432 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211214731243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105607065621 + 105607065622.

It is an arithmetic number, because the mean of its divisors is an integer number (105607065622).

Almost surely, 2211214131243 is an apocalyptic number.

211214131243 is a deficient number, since it is larger than the sum of its proper divisors (1).

211214131243 is an equidigital number, since it uses as much as digits as its factorization.

211214131243 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1152, while the sum is 25.

Adding to 211214131243 its reverse (342131412112), we get a palindrome (553345543355).

The spelling of 211214131243 in words is "two hundred eleven billion, two hundred fourteen million, one hundred thirty-one thousand, two hundred forty-three".