2112149993 has 2 divisors, whose sum is σ = 2112149994. Its totient is φ = 2112149992.

The previous prime is 2112149983. The next prime is 2112150041. The reversal of 2112149993 is 3999412112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1719595024 + 392554969 = 41468^2 + 19813^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112149993 - 2⁶ = 2112149929 is a prime.

It is a super-2 number, since 2×2112149993² = 8922355185859800098, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2112149993.

It is not a weakly prime, because it can be changed into another prime (2112149983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056074996 + 1056074997.

It is an arithmetic number, because the mean of its divisors is an integer number (1056074997).

Almost surely, 2^2112149993 is an apocalyptic number.

It is an amenable number.

2112149993 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112149993 is an equidigital number, since it uses as much as digits as its factorization.

2112149993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34992, while the sum is 41.

The square root of 2112149993 is about 45958.1330451967. The cubic root of 2112149993 is about 1283.0441042400.

The spelling of 2112149993 in words is "two billion, one hundred twelve million, one hundred forty-nine thousand, nine hundred ninety-three".