Base | Representation |
---|---|
bin | 111110111100100… |
… | …1101101000011001 |
3 | 12110012101100011022 |
4 | 1331321031220121 |
5 | 13311202300131 |
6 | 545330412225 |
7 | 103224656561 |
oct | 17571155031 |
9 | 5405340138 |
10 | 2112150041 |
11 | 994287651 |
12 | 4ab431075 |
13 | 278783231 |
14 | 16072dda1 |
15 | c566737b |
hex | 7de4da19 |
2112150041 has 2 divisors, whose sum is σ = 2112150042. Its totient is φ = 2112150040.
The previous prime is 2112149993. The next prime is 2112150121. The reversal of 2112150041 is 1400512112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1377523225 + 734626816 = 37115^2 + 27104^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2112150041 is a prime.
It is a super-2 number, since 2×21121500412 = 8922355591392603362, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2112150641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056075020 + 1056075021.
It is an arithmetic number, because the mean of its divisors is an integer number (1056075021).
Almost surely, 22112150041 is an apocalyptic number.
It is an amenable number.
2112150041 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112150041 is an equidigital number, since it uses as much as digits as its factorization.
2112150041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 17.
The square root of 2112150041 is about 45958.1335674111. The cubic root of 2112150041 is about 1283.0441139593.
Adding to 2112150041 its reverse (1400512112), we get a palindrome (3512662153).
The spelling of 2112150041 in words is "two billion, one hundred twelve million, one hundred fifty thousand, forty-one".
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