211219999993 has 2 divisors, whose sum is σ = 211219999994. Its totient is φ = 211219999992.

The previous prime is 211219999987. The next prime is 211220000021. The reversal of 211219999993 is 399999912112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 157044178944 + 54175821049 = 396288^2 + 232757^2 .

It is a cyclic number.

It is not a de Polignac number, because 211219999993 - 2⁹ = 211219999481 is a prime.

It is a super-3 number, since 3×211219999993³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (211619999993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105609999996 + 105609999997.

It is an arithmetic number, because the mean of its divisors is an integer number (105609999997).

Almost surely, 2^211219999993 is an apocalyptic number.

It is an amenable number.

211219999993 is a deficient number, since it is larger than the sum of its proper divisors (1).

211219999993 is an equidigital number, since it uses as much as digits as its factorization.

211219999993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6377292, while the sum is 64.

The spelling of 211219999993 in words is "two hundred eleven billion, two hundred nineteen million, nine hundred ninety-nine thousand, nine hundred ninety-three".