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211220009914951 is a prime number
BaseRepresentation
bin110000000001101001111101…
…101010010001001001000111
31000200212102202122202102101101
4300001221331222101021013
5210141112040014234301
62025121044421040531
762330066515105462
oct6001517552211107
91020772678672341
10211220009914951
11613349a3114754
121b833a29b56147
1390b1c6646b95b
143a231629c42d9
1519644b5746701
hexc01a7da91247

211220009914951 has 2 divisors, whose sum is σ = 211220009914952. Its totient is φ = 211220009914950.

The previous prime is 211220009914943. The next prime is 211220009914973. The reversal of 211220009914951 is 159419900022112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211220009914951 - 23 = 211220009914943 is a prime.

It is a super-3 number, since 3×2112200099149513 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211220009914931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610004957475 + 105610004957476.

It is an arithmetic number, because the mean of its divisors is an integer number (105610004957476).

Almost surely, 2211220009914951 is an apocalyptic number.

211220009914951 is a deficient number, since it is larger than the sum of its proper divisors (1).

211220009914951 is an equidigital number, since it uses as much as digits as its factorization.

211220009914951 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 116640, while the sum is 46.

The spelling of 211220009914951 in words is "two hundred eleven trillion, two hundred twenty billion, nine million, nine hundred fourteen thousand, nine hundred fifty-one".