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211220120002147 is a prime number
BaseRepresentation
bin110000000001101010000100…
…001110001101111001100011
31000200212110001022220102121221
4300001222010032031321203
5210141112301210032042
62025121103352355511
762330102322612424
oct6001520416157143
91020773038812557
10211220120002147
1161334a4a275903
121b833a5a9a5b97
1390b1c832048c9
143a2317347d64b
1519644c023ed67
hexc01a8438de63

211220120002147 has 2 divisors, whose sum is σ = 211220120002148. Its totient is φ = 211220120002146.

The previous prime is 211220120002121. The next prime is 211220120002159. The reversal of 211220120002147 is 741200021022112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211220120002147 - 219 = 211220119477859 is a prime.

It is a super-2 number, since 2×2112201200021472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211220120008147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610060001073 + 105610060001074.

It is an arithmetic number, because the mean of its divisors is an integer number (105610060001074).

Almost surely, 2211220120002147 is an apocalyptic number.

211220120002147 is a deficient number, since it is larger than the sum of its proper divisors (1).

211220120002147 is an equidigital number, since it uses as much as digits as its factorization.

211220120002147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 896, while the sum is 25.

Adding to 211220120002147 its reverse (741200021022112), we get a palindrome (952420141024259).

The spelling of 211220120002147 in words is "two hundred eleven trillion, two hundred twenty billion, one hundred twenty million, two thousand, one hundred forty-seven".