Base | Representation |
---|---|
bin | 11110101111001001000… |
… | …000001001010111111111 |
3 | 21110220221221012102122201 |
4 | 132233021000021113333 |
5 | 234101242001414101 |
6 | 4254155402052331 |
7 | 305413212656416 |
oct | 36571100112777 |
9 | 7426857172581 |
10 | 2112201201151 |
11 | 7448635709a8 |
12 | 2a1437aaa0a7 |
13 | 124244ac3562 |
14 | 7433414447d |
15 | 39e2347ce01 |
hex | 1ebc90095ff |
2112201201151 has 2 divisors, whose sum is σ = 2112201201152. Its totient is φ = 2112201201150.
The previous prime is 2112201201101. The next prime is 2112201201161. The reversal of 2112201201151 is 1511021022112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2112201201151 - 29 = 2112201200639 is a prime.
It is a super-2 number, since 2×21122012011512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112201201101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056100600575 + 1056100600576.
It is an arithmetic number, because the mean of its divisors is an integer number (1056100600576).
Almost surely, 22112201201151 is an apocalyptic number.
2112201201151 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112201201151 is an equidigital number, since it uses as much as digits as its factorization.
2112201201151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 2112201201151 its reverse (1511021022112), we get a palindrome (3623222223263).
The spelling of 2112201201151 in words is "two trillion, one hundred twelve billion, two hundred one million, two hundred one thousand, one hundred fifty-one".
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