Base | Representation |
---|---|
bin | 1100010010110111000… |
… | …0001011011100001001 |
3 | 202012012100120122110211 |
4 | 3010231300023130021 |
5 | 11430040034030433 |
6 | 241011131041121 |
7 | 21155152615351 |
oct | 3045560133411 |
9 | 665170518424 |
10 | 211221001993 |
11 | 8163a827071 |
12 | 34b295a01a1 |
13 | 16bc1c75321 |
14 | a31a47db61 |
15 | 576361a8cd |
hex | 312dc0b709 |
211221001993 has 2 divisors, whose sum is σ = 211221001994. Its totient is φ = 211221001992.
The previous prime is 211221001969. The next prime is 211221002039. The reversal of 211221001993 is 399100122112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 162467037184 + 48753964809 = 403072^2 + 220803^2 .
It is a cyclic number.
It is not a de Polignac number, because 211221001993 - 213 = 211220993801 is a prime.
It is a super-2 number, since 2×2112210019932 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211221001393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610500996 + 105610500997.
It is an arithmetic number, because the mean of its divisors is an integer number (105610500997).
Almost surely, 2211221001993 is an apocalyptic number.
It is an amenable number.
211221001993 is a deficient number, since it is larger than the sum of its proper divisors (1).
211221001993 is an equidigital number, since it uses as much as digits as its factorization.
211221001993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 31.
The spelling of 211221001993 in words is "two hundred eleven billion, two hundred twenty-one million, one thousand, nine hundred ninety-three".
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