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211221001393 is a prime number
BaseRepresentation
bin1100010010110111000…
…0001011010010110001
3202012012100120121122121
43010231300023102301
511430040034021033
6241011131034241
721155152613533
oct3045560132261
9665170517577
10211221001393
118163a826676
1234b2959b981
1316bc1c74c7c
14a31a47d853
15576361a62d
hex312dc0b4b1

211221001393 has 2 divisors, whose sum is σ = 211221001394. Its totient is φ = 211221001392.

The previous prime is 211221001367. The next prime is 211221001441. The reversal of 211221001393 is 393100122112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114902016784 + 96318984609 = 338972^2 + 310353^2 .

It is a cyclic number.

It is not a de Polignac number, because 211221001393 - 25 = 211221001361 is a prime.

It is a super-2 number, since 2×2112210013932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211221001993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610500696 + 105610500697.

It is an arithmetic number, because the mean of its divisors is an integer number (105610500697).

Almost surely, 2211221001393 is an apocalyptic number.

It is an amenable number.

211221001393 is a deficient number, since it is larger than the sum of its proper divisors (1).

211221001393 is an equidigital number, since it uses as much as digits as its factorization.

211221001393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 211221001393 in words is "two hundred eleven billion, two hundred twenty-one million, one thousand, three hundred ninety-three".