Base | Representation |
---|---|
bin | 110000000001101011111010… |
… | …010111101101001110000111 |
3 | 1000200212122011110202120120112 |
4 | 300001223322113231032013 |
5 | 210141130331130414343 |
6 | 2025122032202023235 |
7 | 62330202412204451 |
oct | 6001537227551607 |
9 | 1020778143676515 |
10 | 211222102201223 |
11 | 61335877164363 |
12 | 1b8343127a7b1b |
13 | 90b220aa88779 |
14 | 3a232c08232d1 |
15 | 1964589288218 |
hex | c01afa5ed387 |
211222102201223 has 2 divisors, whose sum is σ = 211222102201224. Its totient is φ = 211222102201222.
The previous prime is 211222102201051. The next prime is 211222102201247. The reversal of 211222102201223 is 322102201222112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211222102201223 - 210 = 211222102200199 is a prime.
It is a super-2 number, since 2×2112221022012232 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211222102201283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105611051100611 + 105611051100612.
It is an arithmetic number, because the mean of its divisors is an integer number (105611051100612).
Almost surely, 2211222102201223 is an apocalyptic number.
211222102201223 is a deficient number, since it is larger than the sum of its proper divisors (1).
211222102201223 is an equidigital number, since it uses as much as digits as its factorization.
211222102201223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 211222102201223 its reverse (322102201222112), we get a palindrome (533324303423335).
The spelling of 211222102201223 in words is "two hundred eleven trillion, two hundred twenty-two billion, one hundred two million, two hundred one thousand, two hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •