Base | Representation |
---|---|
bin | 110000000001101011111010… |
… | …010111101101011010000111 |
3 | 1000200212122011110202121121222 |
4 | 300001223322113231122013 |
5 | 210141130331130430431 |
6 | 2025122032202030555 |
7 | 62330202412206626 |
oct | 6001537227553207 |
9 | 1020778143677558 |
10 | 211222102201991 |
11 | 613358771649a1 |
12 | 1b8343127a845b |
13 | 90b220aa88c1a |
14 | 3a232c08236bd |
15 | 196458928857b |
hex | c01afa5ed687 |
211222102201991 has 2 divisors, whose sum is σ = 211222102201992. Its totient is φ = 211222102201990.
The previous prime is 211222102201973. The next prime is 211222102202051. The reversal of 211222102201991 is 199102201222112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211222102201991 - 214 = 211222102185607 is a prime.
It is a super-3 number, since 3×2112221022019913 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211222102401991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105611051100995 + 105611051100996.
It is an arithmetic number, because the mean of its divisors is an integer number (105611051100996).
Almost surely, 2211222102201991 is an apocalyptic number.
211222102201991 is a deficient number, since it is larger than the sum of its proper divisors (1).
211222102201991 is an equidigital number, since it uses as much as digits as its factorization.
211222102201991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 35.
The spelling of 211222102201991 in words is "two hundred eleven trillion, two hundred twenty-two billion, one hundred two million, two hundred one thousand, nine hundred ninety-one".
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