2112221113 has 2 divisors, whose sum is σ = 2112221114. Its totient is φ = 2112221112.

The previous prime is 2112221107. The next prime is 2112221129. The reversal of 2112221113 is 3111222112.

It is an a-pointer prime, because the next prime (2112221129) can be obtained adding 2112221113 to its sum of digits (16).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2063612329 + 48608784 = 45427^2 + 6972^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112221113 - 2¹⁷ = 2112090041 is a prime.

It is a super-2 number, since 2×2112221113² = 8922956060405917538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2112221213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056110556 + 1056110557.

It is an arithmetic number, because the mean of its divisors is an integer number (1056110557).

Almost surely, 2^2112221113 is an apocalyptic number.

It is an amenable number.

2112221113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112221113 is an equidigital number, since it uses as much as digits as its factorization.

2112221113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48, while the sum is 16.

The square root of 2112221113 is about 45958.9067863891. The cubic root of 2112221113 is about 1283.0585049017.

Adding to 2112221113 its reverse (3111222112), we get a palindrome (5223443225).

Subtracting 2112221113 from its reverse (3111222112), we obtain a palindrome (999000999).

The spelling of 2112221113 in words is "two billion, one hundred twelve million, two hundred twenty-one thousand, one hundred thirteen".