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21122310031 is a prime number
BaseRepresentation
bin10011101010111111…
…001101111110001111
32000112001100112011221
4103222333031332033
5321224302410111
613411540224211
71345300446544
oct235277157617
960461315157
1021122310031
118a59aa2179
12411599b067
131cb806a304
141045390bcb
1583955c371
hex4eafcdf8f

21122310031 has 2 divisors, whose sum is σ = 21122310032. Its totient is φ = 21122310030.

The previous prime is 21122310023. The next prime is 21122310043. The reversal of 21122310031 is 13001322112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21122310031 - 23 = 21122310023 is a prime.

It is a super-2 number, since 2×211223100312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21122309987 and 21122310014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21122310931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561155015 + 10561155016.

It is an arithmetic number, because the mean of its divisors is an integer number (10561155016).

Almost surely, 221122310031 is an apocalyptic number.

21122310031 is a deficient number, since it is larger than the sum of its proper divisors (1).

21122310031 is an equidigital number, since it uses as much as digits as its factorization.

21122310031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 21122310031 its reverse (13001322112), we get a palindrome (34123632143).

The spelling of 21122310031 in words is "twenty-one billion, one hundred twenty-two million, three hundred ten thousand, thirty-one".