Base | Representation |
---|---|
bin | 11110101111001111100… |
… | …100001001011111110101 |
3 | 21110221020121101010210212 |
4 | 132233033210021133311 |
5 | 234102003143132013 |
6 | 4254214333555205 |
7 | 305416020551504 |
oct | 36571744113765 |
9 | 7427217333725 |
10 | 2112311302133 |
11 | 74490a73144a |
12 | 2a1468945b05 |
13 | 124261862876 |
14 | 74344a0483b |
15 | 39e2ce7a6a8 |
hex | 1ebcf9097f5 |
2112311302133 has 2 divisors, whose sum is σ = 2112311302134. Its totient is φ = 2112311302132.
The previous prime is 2112311302111. The next prime is 2112311302139. The reversal of 2112311302133 is 3312031132112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1870091805169 + 242219496964 = 1367513^2 + 492158^2 .
It is a cyclic number.
It is not a de Polignac number, because 2112311302133 - 210 = 2112311301109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2112311302099 and 2112311302108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112311302139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056155651066 + 1056155651067.
It is an arithmetic number, because the mean of its divisors is an integer number (1056155651067).
Almost surely, 22112311302133 is an apocalyptic number.
It is an amenable number.
2112311302133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112311302133 is an equidigital number, since it uses as much as digits as its factorization.
2112311302133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 2112311302133 its reverse (3312031132112), we get a palindrome (5424342434245).
The spelling of 2112311302133 in words is "two trillion, one hundred twelve billion, three hundred eleven million, three hundred two thousand, one hundred thirty-three".
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