Base | Representation |
---|---|
bin | 1001100110110000111001… |
… | …01011011110110100011111 |
3 | 2202210100111021022101102202 |
4 | 10303120130223132310133 |
5 | 10232040132330302312 |
6 | 112531455422442115 |
7 | 4310044601161064 |
oct | 463303453366437 |
9 | 82710437271382 |
10 | 21123130322207 |
11 | 68042a642a4a1 |
12 | 245197973333b |
13 | ba2b9714a4a4 |
14 | 530517658c6b |
15 | 2696db2da9c2 |
hex | 13361caded1f |
21123130322207 has 2 divisors, whose sum is σ = 21123130322208. Its totient is φ = 21123130322206.
The previous prime is 21123130322183. The next prime is 21123130322237. The reversal of 21123130322207 is 70222303132112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21123130322207 - 26 = 21123130322143 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21123130322207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21123130322237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561565161103 + 10561565161104.
It is an arithmetic number, because the mean of its divisors is an integer number (10561565161104).
Almost surely, 221123130322207 is an apocalyptic number.
21123130322207 is a deficient number, since it is larger than the sum of its proper divisors (1).
21123130322207 is an equidigital number, since it uses as much as digits as its factorization.
21123130322207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 21123130322207 its reverse (70222303132112), we get a palindrome (91345433454319).
The spelling of 21123130322207 in words is "twenty-one trillion, one hundred twenty-three billion, one hundred thirty million, three hundred twenty-two thousand, two hundred seven".
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