Base | Representation |
---|---|
bin | 11110101111010111001… |
… | …111101000110010011011 |
3 | 21110221120120210221020221 |
4 | 132233113033220302123 |
5 | 234102234134034003 |
6 | 4254235215300511 |
7 | 305422143644041 |
oct | 36572717506233 |
9 | 7427516727227 |
10 | 2112440143003 |
11 | 744976431503 |
12 | 2a14a3b1a737 |
13 | 124282463878 |
14 | 74357b82391 |
15 | 39e3942a7bd |
hex | 1ebd73e8c9b |
2112440143003 has 2 divisors, whose sum is σ = 2112440143004. Its totient is φ = 2112440143002.
The previous prime is 2112440142991. The next prime is 2112440143013. The reversal of 2112440143003 is 3003410442112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2112440143003 - 217 = 2112440011931 is a prime.
It is not a weakly prime, because it can be changed into another prime (2112440143013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056220071501 + 1056220071502.
It is an arithmetic number, because the mean of its divisors is an integer number (1056220071502).
Almost surely, 22112440143003 is an apocalyptic number.
2112440143003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112440143003 is an equidigital number, since it uses as much as digits as its factorization.
2112440143003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2112440143003 its reverse (3003410442112), we get a palindrome (5115850585115).
The spelling of 2112440143003 in words is "two trillion, one hundred twelve billion, four hundred forty million, one hundred forty-three thousand, three".
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