Base | Representation |
---|---|
bin | 11110101111011001000… |
… | …101011011000111011001 |
3 | 21110221122201220122112011 |
4 | 132233121011123013121 |
5 | 234102320040114433 |
6 | 4254242241145521 |
7 | 305423000254315 |
oct | 36573105330731 |
9 | 7427581818464 |
10 | 2112471019993 |
11 | 744991900884 |
12 | 2a14b232b2a1 |
13 | 124288984a89 |
14 | 7435bcdcb45 |
15 | 39e3bec93cd |
hex | 1ebd915b1d9 |
2112471019993 has 2 divisors, whose sum is σ = 2112471019994. Its totient is φ = 2112471019992.
The previous prime is 2112471019961. The next prime is 2112471020021. The reversal of 2112471019993 is 3999101742112.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1885107032064 + 227363987929 = 1372992^2 + 476827^2 .
It is a cyclic number.
It is not a de Polignac number, because 2112471019993 - 25 = 2112471019961 is a prime.
It is not a weakly prime, because it can be changed into another prime (2112471019493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056235509996 + 1056235509997.
It is an arithmetic number, because the mean of its divisors is an integer number (1056235509997).
Almost surely, 22112471019993 is an apocalyptic number.
It is an amenable number.
2112471019993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112471019993 is an equidigital number, since it uses as much as digits as its factorization.
2112471019993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 244944, while the sum is 49.
The spelling of 2112471019993 in words is "two trillion, one hundred twelve billion, four hundred seventy-one million, nineteen thousand, nine hundred ninety-three".
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