Base | Representation |
---|---|
bin | 10011101011001001… |
… | …001110011110110001 |
3 | 2000112020021210222102 |
4 | 103223021032132301 |
5 | 321230440333203 |
6 | 13412112350145 |
7 | 1345331654363 |
oct | 235311163661 |
9 | 60466253872 |
10 | 21124933553 |
11 | 8a60524279 |
12 | 4116845355 |
13 | 1cb87784a9 |
14 | 1045874d33 |
15 | 8398c9888 |
hex | 4eb24e7b1 |
21124933553 has 2 divisors, whose sum is σ = 21124933554. Its totient is φ = 21124933552.
The previous prime is 21124933517. The next prime is 21124933559. The reversal of 21124933553 is 35533942112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18876561664 + 2248371889 = 137392^2 + 47417^2 .
It is a cyclic number.
It is not a de Polignac number, because 21124933553 - 214 = 21124917169 is a prime.
It is not a weakly prime, because it can be changed into another prime (21124933559) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10562466776 + 10562466777.
It is an arithmetic number, because the mean of its divisors is an integer number (10562466777).
Almost surely, 221124933553 is an apocalyptic number.
It is an amenable number.
21124933553 is a deficient number, since it is larger than the sum of its proper divisors (1).
21124933553 is an equidigital number, since it uses as much as digits as its factorization.
21124933553 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 97200, while the sum is 38.
The spelling of 21124933553 in words is "twenty-one billion, one hundred twenty-four million, nine hundred thirty-three thousand, five hundred fifty-three".
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