211265641250239 has 2 divisors, whose sum is σ = 211265641250240. Its totient is φ = 211265641250238.

The previous prime is 211265641250119. The next prime is 211265641250329. The reversal of 211265641250239 is 932052146562112.

Together with next prime (211265641250329) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211265641250239 - 2¹¹ = 211265641248191 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211265641250192 and 211265641250201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211265641250539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105632820625119 + 105632820625120.

It is an arithmetic number, because the mean of its divisors is an integer number (105632820625120).

Almost surely, 2^{211265641250239} is an apocalyptic number.

211265641250239 is a deficient number, since it is larger than the sum of its proper divisors (1).

211265641250239 is an equidigital number, since it uses as much as digits as its factorization.

211265641250239 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1555200, while the sum is 49.

The spelling of 211265641250239 in words is "two hundred eleven trillion, two hundred sixty-five billion, six hundred forty-one million, two hundred fifty thousand, two hundred thirty-nine".