Base | Representation |
---|---|
bin | 1001100110111000010111… |
… | …10000100100011001100111 |
3 | 2202210201211210212210000222 |
4 | 10303130023300210121213 |
5 | 10232121341200113112 |
6 | 112533401430154555 |
7 | 4310246154645554 |
oct | 463341360443147 |
9 | 82721753783028 |
10 | 21127141410407 |
11 | 6805a745a741a |
12 | 24526b8ab2a5b |
13 | ba3386151b66 |
14 | 5307b8257a2b |
15 | 269873501372 |
hex | 13370bc24667 |
21127141410407 has 2 divisors, whose sum is σ = 21127141410408. Its totient is φ = 21127141410406.
The previous prime is 21127141410383. The next prime is 21127141410451. The reversal of 21127141410407 is 70401414172112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21127141410407 - 224 = 21127124633191 is a prime.
It is a super-4 number, since 4×211271414104074 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21127141410307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10563570705203 + 10563570705204.
It is an arithmetic number, because the mean of its divisors is an integer number (10563570705204).
Almost surely, 221127141410407 is an apocalyptic number.
21127141410407 is a deficient number, since it is larger than the sum of its proper divisors (1).
21127141410407 is an equidigital number, since it uses as much as digits as its factorization.
21127141410407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12544, while the sum is 35.
Adding to 21127141410407 its reverse (70401414172112), we get a palindrome (91528555582519).
The spelling of 21127141410407 in words is "twenty-one trillion, one hundred twenty-seven billion, one hundred forty-one million, four hundred ten thousand, four hundred seven".
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