Search a number
-
+
21127141410407 is a prime number
BaseRepresentation
bin1001100110111000010111…
…10000100100011001100111
32202210201211210212210000222
410303130023300210121213
510232121341200113112
6112533401430154555
74310246154645554
oct463341360443147
982721753783028
1021127141410407
116805a745a741a
1224526b8ab2a5b
13ba3386151b66
145307b8257a2b
15269873501372
hex13370bc24667

21127141410407 has 2 divisors, whose sum is σ = 21127141410408. Its totient is φ = 21127141410406.

The previous prime is 21127141410383. The next prime is 21127141410451. The reversal of 21127141410407 is 70401414172112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21127141410407 - 224 = 21127124633191 is a prime.

It is a super-4 number, since 4×211271414104074 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21127141410307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10563570705203 + 10563570705204.

It is an arithmetic number, because the mean of its divisors is an integer number (10563570705204).

Almost surely, 221127141410407 is an apocalyptic number.

21127141410407 is a deficient number, since it is larger than the sum of its proper divisors (1).

21127141410407 is an equidigital number, since it uses as much as digits as its factorization.

21127141410407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12544, while the sum is 35.

Adding to 21127141410407 its reverse (70401414172112), we get a palindrome (91528555582519).

The spelling of 21127141410407 in words is "twenty-one trillion, one hundred twenty-seven billion, one hundred forty-one million, four hundred ten thousand, four hundred seven".