Base | Representation |
---|---|
bin | 11110101111101001100… |
… | …111110101001011000101 |
3 | 21110222101001222211100101 |
4 | 132233221213311023011 |
5 | 234103402102200302 |
6 | 4254325552044101 |
7 | 305432606505262 |
oct | 36575147651305 |
9 | 7428331884311 |
10 | 2112748475077 |
11 | 7450144869a9 |
12 | 2a156b233631 |
13 | 1243012bac96 |
14 | 74386ac4269 |
15 | 39e56533287 |
hex | 1ebe99f52c5 |
2112748475077 has 2 divisors, whose sum is σ = 2112748475078. Its totient is φ = 2112748475076.
The previous prime is 2112748475029. The next prime is 2112748475107. The reversal of 2112748475077 is 7705748472112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1444301607681 + 668446867396 = 1201791^2 + 817586^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2112748475077 is a prime.
It is a super-2 number, since 2×21127484750772 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112748472077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056374237538 + 1056374237539.
It is an arithmetic number, because the mean of its divisors is an integer number (1056374237539).
Almost surely, 22112748475077 is an apocalyptic number.
It is an amenable number.
2112748475077 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112748475077 is an equidigital number, since it uses as much as digits as its factorization.
2112748475077 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6146560, while the sum is 55.
The spelling of 2112748475077 in words is "two trillion, one hundred twelve billion, seven hundred forty-eight million, four hundred seventy-five thousand, seventy-seven".
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