Base | Representation |
---|---|
bin | 11110101111101001111… |
… | …011111001110111010101 |
3 | 21110222101102220011120211 |
4 | 132233221323321313111 |
5 | 234103404424042143 |
6 | 4254330300525421 |
7 | 305433002312542 |
oct | 36575173716725 |
9 | 7428342804524 |
10 | 2112753737173 |
11 | 745017450442 |
12 | 2a1570b50871 |
13 | 124302411151 |
14 | 74387693bc9 |
15 | 39e56c2249d |
hex | 1ebe9ef9dd5 |
2112753737173 has 2 divisors, whose sum is σ = 2112753737174. Its totient is φ = 2112753737172.
The previous prime is 2112753737123. The next prime is 2112753737189. The reversal of 2112753737173 is 3717373572112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1205303166769 + 907450570404 = 1097863^2 + 952602^2 .
It is a cyclic number.
It is not a de Polignac number, because 2112753737173 - 217 = 2112753606101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112753737123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056376868586 + 1056376868587.
It is an arithmetic number, because the mean of its divisors is an integer number (1056376868587).
Almost surely, 22112753737173 is an apocalyptic number.
It is an amenable number.
2112753737173 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112753737173 is an equidigital number, since it uses as much as digits as its factorization.
2112753737173 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1296540, while the sum is 49.
The spelling of 2112753737173 in words is "two trillion, one hundred twelve billion, seven hundred fifty-three million, seven hundred thirty-seven thousand, one hundred seventy-three".
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