Base | Representation |
---|---|
bin | 110000000010110100100011… |
… | …100001011000111100111011 |
3 | 1000201011002111102011202101221 |
4 | 300002310203201120330323 |
5 | 210143420102104014302 |
6 | 2025221532104452511 |
7 | 62335633335535615 |
oct | 6002644341307473 |
9 | 1021132442152357 |
10 | 211300102016827 |
11 | 6136596300828a |
12 | 1b84746077a137 |
13 | 90b968b6b0305 |
14 | 3a26d9da95db5 |
15 | 1966601d59937 |
hex | c02d23858f3b |
211300102016827 has 2 divisors, whose sum is σ = 211300102016828. Its totient is φ = 211300102016826.
The previous prime is 211300102016779. The next prime is 211300102016831. The reversal of 211300102016827 is 728610201003112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211300102016827 is a prime.
It is a super-2 number, since 2×2113001020168272 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211300102016792 and 211300102016801.
It is not a weakly prime, because it can be changed into another prime (211300102016327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105650051008413 + 105650051008414.
It is an arithmetic number, because the mean of its divisors is an integer number (105650051008414).
Almost surely, 2211300102016827 is an apocalyptic number.
211300102016827 is a deficient number, since it is larger than the sum of its proper divisors (1).
211300102016827 is an equidigital number, since it uses as much as digits as its factorization.
211300102016827 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 34.
Adding to 211300102016827 its reverse (728610201003112), we get a palindrome (939910303019939).
The spelling of 211300102016827 in words is "two hundred eleven trillion, three hundred billion, one hundred two million, sixteen thousand, eight hundred twenty-seven".
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