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211300102016827 is a prime number
BaseRepresentation
bin110000000010110100100011…
…100001011000111100111011
31000201011002111102011202101221
4300002310203201120330323
5210143420102104014302
62025221532104452511
762335633335535615
oct6002644341307473
91021132442152357
10211300102016827
116136596300828a
121b84746077a137
1390b968b6b0305
143a26d9da95db5
151966601d59937
hexc02d23858f3b

211300102016827 has 2 divisors, whose sum is σ = 211300102016828. Its totient is φ = 211300102016826.

The previous prime is 211300102016779. The next prime is 211300102016831. The reversal of 211300102016827 is 728610201003112.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211300102016827 is a prime.

It is a super-2 number, since 2×2113001020168272 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211300102016792 and 211300102016801.

It is not a weakly prime, because it can be changed into another prime (211300102016327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105650051008413 + 105650051008414.

It is an arithmetic number, because the mean of its divisors is an integer number (105650051008414).

Almost surely, 2211300102016827 is an apocalyptic number.

211300102016827 is a deficient number, since it is larger than the sum of its proper divisors (1).

211300102016827 is an equidigital number, since it uses as much as digits as its factorization.

211300102016827 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 34.

Adding to 211300102016827 its reverse (728610201003112), we get a palindrome (939910303019939).

The spelling of 211300102016827 in words is "two hundred eleven trillion, three hundred billion, one hundred two million, sixteen thousand, eight hundred twenty-seven".