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21130011341 is a prime number
BaseRepresentation
bin10011101011011100…
…100110001011001101
32000112120211210101122
4103223130212023031
5321233240330331
613412413250325
71345423063415
oct235334461315
960476753348
1021130011341
118a6338229a
1241184939a5
131cb98357ba
1410463d7645
1583a07e17b
hex4eb7262cd

21130011341 has 2 divisors, whose sum is σ = 21130011342. Its totient is φ = 21130011340.

The previous prime is 21130011337. The next prime is 21130011347. The reversal of 21130011341 is 14311003112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20698576900 + 431434441 = 143870^2 + 20771^2 .

It is a cyclic number.

It is not a de Polignac number, because 21130011341 - 22 = 21130011337 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21130011347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565005670 + 10565005671.

It is an arithmetic number, because the mean of its divisors is an integer number (10565005671).

Almost surely, 221130011341 is an apocalyptic number.

It is an amenable number.

21130011341 is a deficient number, since it is larger than the sum of its proper divisors (1).

21130011341 is an equidigital number, since it uses as much as digits as its factorization.

21130011341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 21130011341 its reverse (14311003112), we get a palindrome (35441014453).

The spelling of 21130011341 in words is "twenty-one billion, one hundred thirty million, eleven thousand, three hundred forty-one".