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21130031413 is a prime number
BaseRepresentation
bin10011101011011100…
…101011000100110101
32000112120212210221001
4103223130223010311
5321233242001123
613412413523301
71345423206061
oct235334530465
960476783831
1021130031413
118a63396387
1241184a3531
131cb984198a
141046400aa1
1583a0850ad
hex4eb72b135

21130031413 has 2 divisors, whose sum is σ = 21130031414. Its totient is φ = 21130031412.

The previous prime is 21130031407. The next prime is 21130031473. The reversal of 21130031413 is 31413003112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11995068484 + 9134962929 = 109522^2 + 95577^2 .

It is a cyclic number.

It is not a de Polignac number, because 21130031413 - 25 = 21130031381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21130031473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565015706 + 10565015707.

It is an arithmetic number, because the mean of its divisors is an integer number (10565015707).

Almost surely, 221130031413 is an apocalyptic number.

It is an amenable number.

21130031413 is a deficient number, since it is larger than the sum of its proper divisors (1).

21130031413 is an equidigital number, since it uses as much as digits as its factorization.

21130031413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 21130031413 its reverse (31413003112), we get a palindrome (52543034525).

The spelling of 21130031413 in words is "twenty-one billion, one hundred thirty million, thirty-one thousand, four hundred thirteen".